A npn transistor is connected in common emitter configuration

A npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of 800 Ω is connected in the collector circuit and the voltage drop across it is 0.8 V. If the current amplification factor is 0.96 and the input resistance of the circuit is 192Ω, the voltage gain and the power gain of the amplifier will respectively be :

Given: amplification factor α = 0.96
load resistance, R_L = 800 Ω
input resistance, R_i = 192 Ω

So, β =	α	=	0.96	⇒ β = 24
	1 – α		0.04

Voltage gain for common emitter configuration

A_v = β .	R_L	= 24 ×	800	= 100
	R_i		192

Power gain for common emitter configuration
P_v = βA_v = 24 × 100 = 2400
Voltage gain for common base configuration

A_v = α .	R_L	= 0.96 ×	800	= 4
	R_P		192

Power gain for common base configuration
P_v = A_vα = 4 × 0.96 = 3.84