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A nucleus ruptures into two nuclear parts, which have their velocity ratio equal to 2:1.
What will be the ratio of their nuclear size (nuclear radius)?
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- 21/3 : 1
- 1 : 21/3
- 31/2 : 1
- 1 : 31/2
Correct Option: B
Applying law of conservation of momentum,
m1v1 = m2v2
| = | ||||
| v2 | m2 |
| As m = | π r3 ρ | 3 |
⇒ m ∝ r3
Hence,
| = | ||||
| m1 | r31 |
| ∴ | = | |||
| v2 | r31 |
| ⇒ | = |  |  | 1/3 | ||
| r1 | 2 |
