The ratio of the radii of the nuclei 13Al27 and 52Te125

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The ratio of the radii of the nuclei ₁₃Al²⁷ and ₅₂Te¹²⁵ is approximately

1. 6 : 10
2. 13 : 52
3. 40 : 177
4. 14 : 73

Correct Option: A

R ∝ (A)^1/3
∴ R_Al ∝ (27)^1/3 and R_Te ∝ (125)^1/3

∴	R_Al	=	3	=	6
	R_Te		5		10