-
Two radioactive substances A and B have decay constants 5 λ and λ respectively. at t = 0 they have same number of nulei. The ratio of number of nuclei of A to those of B will be (1/e)2 after a time interval
-
- 4 λ
- 2λ
- 1/2λ
- 1/4λ
Correct Option: C
λA = 5λ and λB = λ
At t = 0, (N0)A = (N0)B
Given,
| = | ![]() | ![]() | 2 | |||
| NB | e |
According to radioactive decay,
| = eλt | N0 |
| = eλAt ....(i) | (N0)A |
| = eλBt ....(ii) | (N0)B |
From (1) and (2),
| = e-(5λ - λ)t | NB |
| ⇒ | ![]() | ![]() | 2 | = e-4λt | ![]() | ![]() | 4λt | ||
| e | e |
⇒ 4λt = 2
| ∴ t = | . | 2λ |

