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Two radioactive substances A and B have decay constants 5 λ and λ respectively. at t = 0 they have same number of nulei. The ratio of number of nuclei of A to those of B will be (1/e)2 after a time interval
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- 4 λ
- 2λ
- 1/2λ
- 1/4λ
Correct Option: C
λA = 5λ and λB = λ
At t = 0, (N0)A = (N0)B
Given,
= | 2 | |||||
NB | e |
According to radioactive decay,
= eλt | N0 |
= eλAt ....(i) | (N0)A |
= eλBt ....(ii) | (N0)B |
From (1) and (2),
= e-(5λ - λ)t | NB |
⇒ | 2 | = e-4λt | 4λt | ||||||
e | e |
⇒ 4λt = 2
∴ t = | . | 2λ |