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					 Half-lives of two radioactive substances A and B are respectively 20 minutes and 40 minutes. Initially, the samples of A and B have equal number of nuclei. After 80 minutes the ratio of remaining numbers of A and B nuclei is
 
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- 1 : 16
 - 4 : 1
 - 1 : 4
 - 1 : 1
 
 
Correct Option: C
80 = 20 × nA ⇒  nA = 4 
80 = 40 × nB ⇒ nB = 2
| = | ![]()  | ![]()  | 2 | |||||
| NA | ||||||||
| NB | ![]()  | ![]()  | 2 | |||||
| 2 | 
| = | × | = | ||||
| 2 | 2 | 4 | 

