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Half-lives of two radioactive substances A and B are respectively 20 minutes and 40 minutes. Initially, the samples of A and B have equal number of nuclei. After 80 minutes the ratio of remaining numbers of A and B nuclei is
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- 1 : 16
- 4 : 1
- 1 : 4
- 1 : 1
Correct Option: C
80 = 20 × nA ⇒ nA = 4
80 = 40 × nB ⇒ nB = 2
= | 2 | |||||||
NA | ||||||||
NB | 2 | |||||||
2 |
= | × | = | ||||
2 | 2 | 4 |