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When an α-particle of mass 'm' moving with velocity 'v' bombards on a heavy nucleus of charge 'Ze', its distance of closest approach from the nucleus depends on m as :
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1 m -
1 √m -
1 m2 - m
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Correct Option: A
At closest distance of approach, the kinetic energy of the particle will convert completely into electrostatic potential energy.
Kinetic energy
K.E. = | mv2 | 2 |
Potential energy
P.E. = | r |
mv2 = | ⇒ r ∝ | |||||
2 | r | m |