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Given the value of Rydberg constant is 107 m–1, the wave number of the last line of the Balmer series in hydrogen spectrum will be :
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- 0.025 × 104 m–1
- 0.5 × 107 m–1
- 0.25 × 107 m–1
- 2.5 × 107 m–1
Correct Option: C
According to Bohr's theory, the wave number of the last line of the Balmer series in hydrogen spectrum,
For hydrogen atom z = 1
| = RZ2 |  | - |  | ||||
| λ | n22 | n21 |
| = 107 × 12 | | - | | |||
| n2 | ∞2 |
| ⇒ wave number | = 0.25 × 107 m-1 | λ |
