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The wavelength of the first line of Lyman series for hydrogen atom is equal to that of the second line of Balmer series for a hydrogen like ion. The atomic number Z of hydrogen like ion is
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- 3
- 4
- 1
- 2
Correct Option: D
For first line of Lyman series of hydrogen
= Rhc | - | |||||||
λ1 | 12 | 22 |
For second line of Balmer series of hydrogen like ion
= R2hc | - | |||||||
λ2 | 22 | 42 |
By question, λ1 = λ2
⇒ | - | 1 | 2 |
= Z2 | - | or Z = 2 | 4 | 16 |