The ground state energy of hydrogen atom is 13.6eV. When

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The ground state energy of hydrogen atom is 13.6eV. When its electron is in the first excited state, its excitation energy is

When the electron is in first excited state (n = 2), the excitation energy is given by

∆E = E₂ – E₁
We have,

E_n = -	13.6	eV
	n²

∴ E₂ = -	13.6	= - 3.4eV
	2²

Given E₁ = –13.6eV
∴ ∆ E = ( – 3.4) – ( – 13.6) = 10.2 eV.