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The total energy of an electron in the first excited state of hydrogen atom is about –3.4 eV. Its kinetic energy in this state is
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- 3.4 eV
- 6.8 eV
- –3.4 eV
- –6.8 eV
Correct Option: A
K.E = | (13.6 eV) | n2 |
Mechanical energy = | (13.6 eV) | n2 |
∴ K.E. in 2nd orbital for hydrogen = – Mechanical energy
= | (13.6) = + 3.4 eV | 22 |