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  1. The ionization energy of hydrogen atom is 13.6 eV. Following Bohr’s theory, the energy corresponding to a transition between 3rd and 4th orbit is
    1. 3.40 eV
    2. 1.51 eV
    3. 0.85 eV
    4. 0.66 eV
Correct Option: D

E = E4 – E3

= -
13.6
--
13.6
= - 0.85 + 1.51 = 0.66 eV
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