-
A source S1 is producing, 1015 photons per second of wavelength 5000 Å. Another source S1 is producing 1.02×1015 photons per second of wavelength 5100 Å Then,
(power of S2) (power of S1) is equal to :
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- 1.00
- 1.02
- 1.04
- 0.98
Correct Option: A
Energy emitted/sec by
| S1, P1 = n1 | λ1 |
Energy emitted/sec by
| S2, P2 = n2 | λ2 |
| ∴ | = | . | ||||
| P1 | n1 | λ2 |
| = | . | = 1.0 | ||
| 1015 | 5100 |
