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The potential difference that must be applied to stop the fastest photo electrons emitted by a nickel surface, having work function 5.01 eV, when ultraviolet light of 200 nm falls on it, must be:
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- 2.4 V
- – 1.2 V
- – 2.4 V
- 1.2 V
Correct Option: D
| Kmax = | - W = | - 5.01 | ||
| λ | λ |
| = | - 5.01 | λ(in Å) |
| = | - 5.01 | 2000 |
= 6.1875 – 5.01 = 1.17775 ≃ 1.2 V
