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A car accelerates from rest at a constant rate α for some time, after which it decelerates at a constant rate β and comes to rest. If the total time elapsed is t, then the maximum velocity acquired by the car is
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α² + β² 
t αβ -

α² - β² 
t αβ -
(α + β) t αβ -
αβ t α + β
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Correct Option: D

In Fig.
AA1 = vmax. = αt1 = βt2
But t = t1 + t2 = vmax./α + vmax./β
| = vmax. | ![]() | + | ![]() | = vmax. | ![]() | ![]() | |||
| α | β | αβ |
| or, = vmax. = t | ![]() | ![]() | |
| α + β |