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A particle moves along a straight line such that its displacement at any time t is given by s = (t³ – 6t² + 3t + 4) metres The velocity when the acceleration is zero is
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- 3 ms–1
- – 12 ms–1
- 42 ms–2
- – 9 ms–1
Correct Option: D
| Velocity, v = | = 3t² 12t + 3 | |
| dt |
| Acceleration, a = | = 6t² - 12t | |
| dt |
For a = 0, we have, 0 = 6 t – 12 or t = 2s. Hence, at t = 2 s the velocity will be
