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A stone is dropped from a height h. It hits the ground with a certain momentum P. If the same stone is dropped from a height 100% more than the previous height, the momentum when it hits the ground will change by :
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- 68%
- 41%
- 200%
- 100%
Correct Option: B
Momentum P = mv = m√2gh
(∵ v² = u² + 2gh; Here u = 0)
When stone hits the ground momentum P = m√2gh
when same stone dropped from 2h (100% of initial) then momentum
P′= m√2gh(2h) = √2P
Which is changed by 41% of initial.
