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A 3 kg ball strikes a heavy rigid wall with a speed of 10 m/s at an angle of 60º. It gets reflected with the same speed and angle as shown here. If the ball is in contact with the wall for 0.20s, what is the average force exerted on the ball by the wall?
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- 150 N
- zero
- 150√3N
- 300 N
Correct Option: C
Change in momentum along the wall
= mv cos60º – mv cos 60º = 0
Change in momentum perpendicular to the wall
= mv sin60º – (– mv sin60º) = 2mv sin60º
| ∴ Applied force = | ||
| Time |
| = | ||
| 0.20 |
| = | = 50 × 3√3 | |
| 2 × 20 |
= 150√3 newton
