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A bullet is fired from a gun. The force on the bullet is given by F = 600 – 2 × 105 t where, F is in newton and t in second. The force on the bullet becomes zero as soon as it leaves the barrel. What is the average impulse imparted to the bullet?
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- 1.8 N-s
- zero
- 9 N-s
- 0.9 N-s
Correct Option: D
Given F = 600 - (2 &time; 105t)
The force is zero at time t, given by
⇒ t = | = 3 × 10-3 second | |
2 &time; 105 |

= | ![]() | 600t - | ![]() | 3 × 10-3 | |
2 | 0 |
= 300 &time; 3 &time; 10-3 - 105(3 × 10-3)²
= 1.8 - 0.9 = 0.9Ns