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The coefficient of static friction, µs, between block A of mass 2 kg and the table as shown in the figure is 0.2. What would be the maximum mass value of block B so that the two blocks do not move? The string and the pulley are assumed to be smooth and massless.
(g = 10 m/s²) [2004]
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- 0.4 kg
- 2.0 kg
- 4.0 kg
- 0.2 kg
Correct Option: A
mBg = µs mAg {∵ mAg = µs mAg}
⇒ mB = µs mA
or, mB = 0.2 × 2 = 0.4 kg