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The equation for a transverse wave travelling along the positive x-axis with amplitude 0.2 m, velocity v =360 ms–1 and wavelength λ = 60 m can be written as
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y - 0.2sin = 2π 6t + x 60 -
y - 0.2sin = π 6t + x 60 -
y - 0.2sin = 2π 6t - x 60 -
y - 0.2sin 2π 6t + x 60
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Correct Option: A
v = nλ
⇒ n - | - | - 6 | ||
λ | 60 |
a = 0.2
For a wave travelling along positive x-axis
y = a sin (ωt – kx)
= a sin | ![]() | 2πnt - | ![]() | ||
λ |
= a sin | ![]() | nt - | ![]() | = 0.2 sin2π | ![]() | 6t - | ![]() | ||
λ | 60 |