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The phase difference between two waves, represented by
y1 = 10–6 sin{100 t + (x/50) + 0.5} m
y1 = 10–6 cos{100 t + (x/50)} m
where x is expressed in metres and t is expressed in seconds, is approximately
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- 1.5 radians
- 1.07 radians
- 2.07 radians
- 0.5 radians
Correct Option: B
y1 = 10–6 sin (100 t + x/50 + 0.5)m
= 10–6 cos (100 t + x/50 – π/2 + 0.5)m
y2 = 10–6 cos (100 t + x/50)m
∴ φ = π/2 – 0.5 = 1.07 rad
