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A transverse wave is represented by the equation
y - y0sin 2π (yl - x) π
For what value of λ is the maximum particle velocity equal to two times the wave velocity?
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- λ = 2πyU
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λ = πyU 3 -
λ = πyU 2 - λ = 2πy∏
Correct Option: D
y = y0 sin | (vy - x) | |
λ |
Particle velocity
= y0 × | v cos × | (vt - x) | ||||
dt | λ | λ |
Maximum particle velocity = y0 × | ||
λ |
Wave velocity = v [given]
So, y0 × | = 2v | |
λ |
λ = π.y0