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A block of mass 1 kg is placed on a truck which accelerates with acceleration 5m/s². The coefficient of static friction between the block and truck is 0.6. The frictional force acting on the block is
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- 5 N
- 6 N
- 5.88 N
- 4.6 N
Correct Option: A
Maximum friction force = µmg
= .6 × 1 × 9.8 = 5.88 N
But here required friction force
= ma = 1 × 5 = 5 N