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Starting from rest, a body slides down a 45° inclined plane in twice the time it takes to slide down the same distance in the absence of friction. The coefficient of friction between the body and the inclined plane is
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- 0.80
- 0.75
- 0.25
- 0.33
Correct Option: B
In presence of friction a = (g sinθ – µg cos θ)
∴ Time taken to slide down the plane
| t1 = √ | = √ | = 48 | ||
| a | g(sinθ - μ cosθ) |
| In absence of friction t2 = √ | ||
| g sinθ |
t1 2t2
&there; t1² 4t2²
| or = | = | |||
| g(sinθ - μcosθ) | gsinθ |
sin θ = 4 sinθ – 4µ cos θ
| μ = | tanθ = | = 0.75 | ||
| 4 | 4 |
