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Two stones of masses m and 2m are whirled in horizontal circles, the heavier one in radius 1/2 and the lighter one in radius r. The tangential speed of lighter stone is n times that of the value of heavier stone when they experience same centripetal forces. The value of n is :
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- 3
- 4
- 1
- 2
Correct Option: D
According to question, two stones experience same centripetal force
i.e. FC1 = FC2
or, | = | |||
r | r/2 |
or, v1² = 4v2²
So, V1 = 2V2 i.e., n = 2