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A particle of mass M is moving in a horizontal circle of radius R with uniform speed V. When it moves from one point to a diametrically opposite point, its
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- kinetic energy changes by MV²/4
- momentum does not change
- momentum changes by 2 MV
- kinetic energy changes by MV²
Correct Option: C
On the diametrically opposite points, the velocities have same magnitude but opposite directions. Therefore, change in momentum is MV – (– MV) = 2MV
