Concrete structures miscellaneous


Concrete structures miscellaneous

Concrete Structures

  1. Maximum strain in an extreme fibre in concrete and in the tension reinforcement (Fe-415 grade and Es = 200 kN/mm2) in a balanced section at limit state of flexure are respectively









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    Max strain in steel

    = 0.002 +
    0.87 fy
    Es

    = 0.002 +
    0.87 × 415
    = 0.0038
    200 × 103

    For concrete max strain = 0.0035

    Correct Option: A

    Max strain in steel

    = 0.002 +
    0.87 fy
    Es

    = 0.002 +
    0.87 × 415
    = 0.0038
    200 × 103

    For concrete max strain = 0.0035


  1. As per the provisions of IS 456-2000, the (short-term) modulus of elasticity of M 25 grade concrete (in N/mm2) can be assumed to be









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    EC = 5000 √25
    = 25000 MPa

    Correct Option: A

    EC = 5000 √25
    = 25000 MPa



  1. As per provisions of IS 456-2000, in the limit state method for design of beams, the limiting value of the depth of neutral axis in a reinforced concrete beam of effective depth ‘d’ is given as









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    Limiting value of depth of neutral axis depends on grade of concrete.

    Correct Option: D

    Limiting value of depth of neutral axis depends on grade of concrete.


  1. Match the information related to tests on aggregates given in Group-I with that in Group-II
    Group-I
    P. Resistance to impact
    Q. Resistance to wear
    R. Resistance to weathering action
    S. Resistance to crushing
    Group-II
    1. Hardness
    2. Strength
    3. Toughness
    4. Soundness









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    Resistance to impact – Toughness
    Resistance to wear – Hardness
    Resistance to weathering action – Soundness
    Resistance to crushing – Strength

    Correct Option: B

    Resistance to impact – Toughness
    Resistance to wear – Hardness
    Resistance to weathering action – Soundness
    Resistance to crushing – Strength



  1. Top ring beam of an Intze tank carries a hoop tension of 120 kN. the beam cross-section is 250 mm wide the 400 mm deep and it is reinforced with 4 bars of 20 mm diameter of Fe 415 grade. Modular ratio of the concrete is 10. The tensile stress in N/ mm2 in the concrete is









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    Area of reinforcement

    = 4 ×
    π
    × 202 = 1256.63 mm2
    4

    Equivalent area of concrete = m. Ast + (250 × 400 – Ast)
    = 10 × 1256.6 + (250 × 400 – 1256.6)
    = 111309.6 mm2
    Stress in concrete
    =
    120 × 103
    = 1.078 N/mm2
    11309.6

    Correct Option: B

    Area of reinforcement

    = 4 ×
    π
    × 202 = 1256.63 mm2
    4

    Equivalent area of concrete = m. Ast + (250 × 400 – Ast)
    = 10 × 1256.6 + (250 × 400 – 1256.6)
    = 111309.6 mm2
    Stress in concrete
    =
    120 × 103
    = 1.078 N/mm2
    11309.6