System of Particles and Rotational Motion
- A fly wheel rotating about a fixed axis has a kinetic energy of 360 joule when its angular speed is 30 radian/sec. The moment of inertia of the wheel about the axis of rotation is
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Er = 1 Iω² 2 I = 2Er = 2 × 360 = 0.8 kgm² ω² 30 × 30 Correct Option: C
Er = 1 Iω² 2 I = 2Er = 2 × 360 = 0.8 kgm² ω² 30 × 30
- A composite disc is to be made using equal masses of aluminium and iron so that it has as high a moment of inertia as possible. This is possible when
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Density of iron > density of aluminium
∴ Since, ρiron > ρaluminium
So, whole of aluminium is kept in the core and the iron at the outer rim of the disc.Correct Option: B
Density of iron > density of aluminium
∴ Since, ρiron > ρaluminium
So, whole of aluminium is kept in the core and the iron at the outer rim of the disc.
- A thin uniform circular ring is rolling down an inclined plane of inclination 30° without slipping. Its linear acceleration along the inclination plane will be
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a = g sinθ = g sin 30° = g 1 + K²/R² 1 + 1 4 Correct Option: C
a = g sinθ = g sin 30° = g 1 + K²/R² 1 + 1 4
- Angular momentum is
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Angular momentum →L is defined as
→L = r' × m(v')
So, L' is an axial vector.Correct Option: A
Angular momentum →L is defined as
→L = r' × m(v')
So, L' is an axial vector.
- The angular momentum of a body with mass (m), moment of inertia (I) and angular velocity (ω) rad/sec is equal to
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Let body contain m1, m2, m3........mn masses at distance r1, r2, r3 ........ rn from axis OA.
Angular momentum of body
= m1v1r1 + m2v2r2 .....+ mnvnrn
= m1(ωr1)r1 + m2(ωr2)r2 .......... + mn(ωrn)rn
= (m1r1²)ω + (m2r2²)ω .......... + (mnrn²)ωCorrect Option: A
Let body contain m1, m2, m3........mn masses at distance r1, r2, r3 ........ rn from axis OA.
Angular momentum of body
= m1v1r1 + m2v2r2 .....+ mnvnrn
= m1(ωr1)r1 + m2(ωr2)r2 .......... + mn(ωrn)rn
= (m1r1²)ω + (m2r2²)ω .......... + (mnrn²)ω