Mechanical Properties of Fluids

Mechanical Properties of Fluids

Easy Questions

Mechanics

Physical World, Units and Measurements
Motion in a Straight Line
Motion in a Plane
Laws of Motion
Work, Energy and Power
Gravitation
Mechanical Properties of Solids
Mechanical Properties of Fluids
System of Particles and Rotational Motion
  1. The approximate depth of an ocean is 2700 m. The compressibility of water is 45.4 × 10–11 Pa–1 and density of water is 103 kg/m3.What fractional compression of water will be obtained at the bottom of the ocean ?​








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    Compressibility of water, ​K = 45.4 × 10–11 Pa–1
    density of water P = 103 kg/m3 ​
    depth of ocean, h = 2700 m
    ​

    We have to find
    ∆V
    		 = ?
    V

    As we know, compressibility,
    =
    1
    		 =
    (∆V / V)
    		 (P = ρ g h)
    BP

    So , (∆V / V) = K ρ g h
    = 45.4 × 10–11 × 103 × 10 × 2700  = 1.2258 × 10–2

    Correct Option: B

    Compressibility of water, ​K = 45.4 × 10–11 Pa–1
    density of water P = 103 kg/m3 ​
    depth of ocean, h = 2700 m
    ​

    We have to find
    ∆V
    		 = ?
    V

    As we know, compressibility,
    =
    1
    		 =
    (∆V / V)
    		 (P = ρ g h)
    BP

    So , (∆V / V) = K ρ g h
    = 45.4 × 10–11 × 103 × 10 × 2700  = 1.2258 × 10–2

  1. Two non-mixing liquids of densities ρ and nρ (n > 1) are put in a container. The height of each liquid is h. A solid cylinder of length L and density d is put in this container. The cylinder floats with its axis vertical and length pL(p < 1) in the denser liquid. The density d is equal to :








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    As we know, ​Pressure P = Vdg

    Here, L A d g = (pL) A (nρ)g + (1 – p)L A ρ g
    ​⇒ ​d = (1 – p)ρ + pn ρ = [1 + (n – 1)p]ρ

    Correct Option: D

    As we know, ​Pressure P = Vdg

    Here, L A d g = (pL) A (nρ)g + (1 – p)L A ρ g
    ​⇒ ​d = (1 – p)ρ + pn ρ = [1 + (n – 1)p]ρ

  1. A U tube with both ends open to the atmosphere, is partially filled with water. Oil, which is immiscible with water, is poured into one side until it stands at a distance of 10 mm above the water level on the other side. Meanwhile the water rises by 65 mm from its original level (see diagram). The density of the oil is​​​​








  1. View Hint View Answer Discuss in Forum

    Here, hoil × ρoil × g = hwater × ρwater × g
    ​ρo g × 140 × 10–3 = ρw g × 130 × 10–3

    ρoil =
    130
    		 × 103 ≈ 928 kg / m3
    140

    [ ∵ ρw = 1 kgm–3]

    Correct Option: C

    Here, hoil × ρoil × g = hwater × ρwater × g
    ​ρo g × 140 × 10–3 = ρw g × 130 × 10–3

    ρoil =
    130
    		 × 103 ≈ 928 kg / m3
    140

    [ ∵ ρw = 1 kgm–3]