Irrigation miscellaneous
- The culturable command area for a distributary channel is 20,000 hectares. Wheat is grown in the entire area and the intensity of irrigation is 50%. The kor period for wheat is 30 days and the kor water depth is 120 mm. The outlet discharge for the distributary should be
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Effective area to be irrigated = 20000 × 50% = 10000 hectares
Kor period = 30 days(Period of irrigation)
Kor depth = 120 mm
Volume of water = 10000 × 10–4 × 120 × 10–3Discharge, Q = 10000 × 120 × 10–4 × 10–3 (days to seconds) = 4.63 m³/s. 30 × 24 × 60 × 60 Correct Option: C
Effective area to be irrigated = 20000 × 50% = 10000 hectares
Kor period = 30 days(Period of irrigation)
Kor depth = 120 mm
Volume of water = 10000 × 10–4 × 120 × 10–3Discharge, Q = 10000 × 120 × 10–4 × 10–3 (days to seconds) = 4.63 m³/s. 30 × 24 × 60 × 60
Direction: The moisture holding capacity of the soil in a 100 hectare farm is 18 cm/m, the field is to be irrigated when 50 per cent of the available moisture in the root zone is depleted. The irrigation water is to be supplied by a pump working for 10 hours a day, and water application efficiency is 75%. Details of crops planned for cultivation area are as follows:
[2010, 2 marks each]
- The capacity of irrigation system required to irrigate crop X in 36 hectares is
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Moisture holding capacity = 18 cm/m.
When moisture level is 250%, irrigation is required.
∴ Moisture held by soil = 9 cm/mQuantity of water = (36 × 104) × 0.09 (75% efficiency) = 43200 m³. 0.75 Discharge of pump = 43200 = 0.066 m³/s = = 66.6 L/s 18 × 10 × 60 × 60 Correct Option: B
Moisture holding capacity = 18 cm/m.
When moisture level is 250%, irrigation is required.
∴ Moisture held by soil = 9 cm/mQuantity of water = (36 × 104) × 0.09 (75% efficiency) = 43200 m³. 0.75 Discharge of pump = 43200 = 0.066 m³/s = = 66.6 L/s 18 × 10 × 60 × 60