The i-v characteristics of the diode in the circuit given

The i-v characteristics of the diode in the circuit given below are

The current in the circuit is

10 = (1000)i + v

=	1000(v - 0.7)	+ v
	500

= 2(v – 0.7) + v = 2v – 1.4 + v = 3v – 1.4
⇒ 3v – 1.4 = 10
⇒ 3v = 10 + 1.4 = 11.4

⇒ v =	11.4	= 3.8
	3

∴ i =	v - 0.7
	500

=	3.8 - 0.7	= 6.2 mA
	500