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The fully controlled thyristor converter in the given figure is fed from a single-phase source. When the firing angle is 0°, the dc output voltage of the converter is 300 V. What will be the output voltage for a firing angle of 60°, assuming continuous conduction?
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- 150 V
- 210 V
- 300 V
- 100 π V
Correct Option: A
For Fully Controlled Converter (FCC)
| Average output voltage, V0 = | cos α (V = rms) | |
| π |
For α = 0, V0 = 300
| ∴ 300 = | .V | |
| π |
| ⇒ V = | ||
| 2 √2 |
| A α = 60 , V0 = |  |  | .cos 60 | ||
| π | 2 √2 |
| = 300 × | = 150 V | |
| 2 |
