The circuit shows an ideal diode connected to a pure inductor

The circuit shows an ideal diode connected to a pure inductor and is connect ed to a purely sinusoidal 50Hz voltage source. Under ideal conditions, the current waveform through the inductor will look like

v_L = L	di	, i =	1	∫vdt
	dt		2

For 0 < ω t < π , v_L = v_in = 10 sin ω t =	di
	dt

∴ i =	1	∫vdt =	π	∫10 sin100 π t dt
	L		0.1

⇒ i = – cos 100π t + c

At 100π t =	π	, i = 0 ⇒ c = 0
	2

∴ i = – cos 100 πt
∴ i_peak = 1A
For π < ω t, v_L = v_in = 0