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A diode circuit feeds an ideal inductor as shown in the figure. Given vs = 100 sin(ωt) V, where ω = 100π rad/s, and L = 31.83 mH. The initial value of inductor current is zero. Switch S is closed at t = 2.5 ms. The peak value of inductor current iL (in A) in the first cycle is ________.
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- 17.07 A
- 17 A
- 170.7 A
- 10.70 A
Correct Option: A
When S is closed VL = Vs
| ∴ L | = Vm sin ωt | |
| dt |
| di = | sin ωt . dt but ω = 100π rad / sec | |
| L |
f = 50 Hg ⇒ T = 20 msa
Integrate on both sides
Current Ic is changing from 0 to max density their period.
| = - | [cos(100π × 10 × 10-3) - cos(100π × 2.5 × 10-3)] | |
| ωL |
| = - |  | cosπ - cos |  | |||
| ωL | 4 |
| ∴ Imax = | [1 + 0.707] = 17.07 A | |
| 100π × 31.83 × 10-3 |
