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In the circuit given in the figure, if both transistor Q1 and Q2 are identical, then output voltage at T = 300 K is
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2 log10 υ2 R1 υ1 R2 -
log10 υ2 R1 υ1 R2 -
2.303 log10 υ2 R1 υ1 R2 -
4.605 log10 υ2 R1 υ1 R2
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Correct Option: B
υ0 = | (υ01 - υ02) | |
20 |
υ01 = -υBE1 - Vt ln | ![]() | ![]() | ||
is |
υ02 = -υBE2 - Vt ln | ![]() | ![]() | ||
is |
υ01 - υ02 = - Vt ln | ![]() | ![]() | = Vt ln | ![]() | ![]() | ||
ic2 | ic1 |
ic1 = | , ic2 = | ||
R1 | R2 |
υ01 - υ02 = Vt ln | ![]() | ![]() | , Vt = 0.0259 V | ||
R2 | υ1 |
υ0 = | (υ01 - υ02) | |
20 |
= | (0.0259) ln | ![]() | ![]() | = 0.4329 ln | ![]() | ![]() | |||||
20 | υ1 | R2 | υ1 | R2 |
= 0.4329 (2.3026) l0g10 | ![]() | ![]() | = l0g10 | ![]() | ![]() | ||||
υ1 | R2 | υ1 | R2 |