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If an npn transistor has a beta cut-off frequency fB of 1MHz, and emitter short circuit low frequency current gain β0 of 200, then unity gain frequency fT and alpha cut off frequency fα respectively are
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- 200 MHz, 201 MHz
- 200 MHz, 199 MHz
- 199 MHz, 200 MHz
- 201 MHz, 200 MHz
Correct Option: A
f T = β0 × fβ = (200) × 1 MHz = 200 MHz
and fα = | = | ||||||
1 - α | 1 - | ||||||
1 + β |
= f β (β+ 1) = 106 (200 + 1) 106 × 201 = 201 MHz