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The transfer function of a second order LP filter shown in the given figure is
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1 R2C2s2 + 3RCs + 1 -
RCs R2C2s2 + 3RCs + 1 -
R2C2s2 + 1 R2C2s2 + 3RCs + 1 -
R2C2s2 R2C2s2 + 3RCs + 1
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Correct Option: A
Using ∆ – Y conversion,
| Z1 = | |
| 2RCs + 1 |
| Z2 = | |
| 2RCs + 1 |
| Z3 = | |
| 2RCs + 1 |
From the figure, using KCL, we have
| = | |||
| Vin | R2C2s2 + 3RCs + 1 |
