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The transistor in the given circuit should always be in active region. Take VCE (sat) = 0.2 V. VBE = 0.7V. The maximum value of Rc in Ω which can be used, is ______
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- 22 to 23
- 12 to 20
- 14
- 19.99
Correct Option: A
In B-E loop, using KVL, we have
5 – 2KIB – VBE = 0
⇒ IB = | = 2.15 mA | |
2K |
and IC = βIB = 100 × 2.15 mA = 215 mA
Using KVL in C-E loop, we get
VCE = 5 – 0.215 RC
For active region, VCE > 0.2 V
⇒ 0.215 RC < 5 – 0.2
⇒ RC = | ≅ 22.32 Ω | |
0.215 |