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Control system miscellaneous

  1. Given : KKt = 99; s = j1 rad/s
    The sensitivity of the closed-loop system (shown in the figure) to variation in parameter K is approximately

    1. 0.01
    2. 0.1
    3. 1.0
    4. 10
Correct Option: B

Given : KKt = 99; s = j1 rad/sec.

SKM =
dM
M =
K
dM
1 +
10
MdK
K

Now M =
G
=
K
=
K
(10s + 1)
1 + GH1 +
KKt
10s + 1 + KKt
(10s + 1)

dM
=
1 × (10s + 1 + KKt) - KKt
dK(10s + 1 + KKt)2

=
10s + 1
(10s + 1 + KKt)2

K
dM
=
K
MdK
K
(10s + 1 + KKt)

=
(10s + 1)
(10s + 1 + KKt)2

=
(10s + 1)
(10s + 1 + KKt)

=
(10s + 1)
10(10 + s)

With s = j1,
K
dM
=
100 + 1
= 0.1
MdK10 √100 + 1



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