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The system with the open loop transfer function G(s) H(s) = 1 has a gain margin of s(s2 + s + 1)
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- – 6 dB
- 0 dB
- 3.5 dB
- 6 dB
Correct Option: B
∠ G(jω) H(jω) = – 180°
= -90° - tan– 1 | ||
1 - ω2 |
since G(jω) H(jω) = | ![]() | ![]() | ||
jω(jω + 1 - ω2) |
⇒ tan– 1 | = 90° | |
1 - ω2 |
K > 0
∴ ω = 1 rad / sec
Then, GM = – log|G(jω), H(jω )| ω = 1 | = 0 dB