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The maximum phase shift that can be provided by a lead compensator with transfer function
G(s) = 1 + 6s is 1 + 2s
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- 15°
- 30°
- 45°
- 60°
Correct Option: B
| G(s) = | ||
| 1 + 2s |
Phase shift, φ = tan– 16ω – tan– 12ω
| = | - | |||||
| dω | 1 + 36ω2 | 1 + 4ω2 |
| For maximum value of φ , | = 0 | |
| dω |
∴ 3 (1+ 4ω2) = 1 + 36 ω2
or ω = 1/ √12
| Thus , φ = tan– 1 | - tan– 1 | = 30° | ||
| 12 | √3 |
