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The maximum phase shift that can be obtained by using a lead compensator with transfer function
GC(s) = 4(1 + 0.15s) is equal to (1 + 0.005s)
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- 15°
- 30°
- 45°
- 60°
Correct Option: B
For phase-shift only | ![]() | ![]() | is important. | |
1 + 0.005 s |
It is identified that T = 0.05 and aT = 0.15
⇒ a = 3
Maximum phase shift is given by φm such that
tan φm = | = | = | |||
2 √a | 2 √3 | √3 |
∴ φm = 30°