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The system Ẋ = 2 3 X + 1 u is 0 5 0
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- controllable but unstable
- uncontrollable and unstable
- controllable and stable
- uncontrollable and stable
Correct Option: B
Ẋ = | ![]() | 2 | ![]() | X + | ![]() | ![]() | u | ||||
0 | 0 |
B = | ![]() | 1 | ![]() | , A = | ![]() | 2 | ![]() | |||
0 | 0 | 5 |
AB = | ![]() | 2 | ![]() | ![]() | ![]() | = | ![]() | ![]() | |||||
0 | 0 | 0 |
⇒ [B : AB] = | ![]() | ![]() | |||||
This is not a 2 × 2 matrix, hence system is uncontrollable
Now [sI - A] = | ![]() | s | ![]() | - | ![]() | 2 | 3 | ![]() | ||||||
0 | s | 0 | 5 |
= | ![]() | ![]() | |||||
= (s – 2) (s – 5)
Two roots on positive half of the y-axis, hence the system is unstable .