A 3 phase, 50 Hz, six pole induction motor has a rotor resistance

A 3 phase, 50 Hz, six pole induction motor has a rotor resistance of 0.1 Ω and reactance of 0.92 Ω. Neglect the voltage drop in stator and assume that the rotor resistance is constant. Given that the full load slip is 3%, the ratio of maximum torque to full load torque is

Given, P = b , f = 50Hz
R₂ = 0.1 Ω , X₂ = 0.092 Ω
S_f1 = 3% = 0.03
T_max = ?
As we know that

=	T_max
	T_f1

=	S²_m + S²_f1
	2S_m S_f1

∴	T_max	=	S²_m + S²_f1
	2S_m S_f1		2S_m S_f1

Now , S_m =	R₂	=	0.1	= 0.108 = 0.03
	x₂		0.92

∴	T_max	=	(0.108)² + (0.03)²	= 1.938 ≈ 1.94
	2S_m S_f1		2(0.108) (0.03)