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For a single phase, two winding transformer, the supply frequency and voltage are both increased by 10%. The percentage changes in the hysteresis loss and eddy current loss, respectively, are
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- 10 and 21
- – 10 and 21
- 21 and 10
- – 21 and 10
Correct Option: A
Hysteresis loss Ph α f B2m α f | ![]() | ![]() | x | α f1 - x Vx | |
f |
Percentage change in Ph ,
∆Ph = | ![]() | × 100 | ![]() | % | |
Ph1 |
= | ![]() | × 100 | ![]() | % | |
f1 - x Vx |
= [(1.1)1 - x (1.1)x – 1] × 100%
= [1.1 – 1] × 100 = 10%
Percentage change in Pe,
∆Pe = | ![]() | × 100 | ![]() | % | |
Pe1 |
= | ![]() | × 100 | ![]() | % | |
V2 |
= [1(1.21 – 1) × 100 ] % = 21%