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A single-phase transformer has no-load loss of 64 W, as obtained from an open-circuit test. When a short-circuit test is performed on it with 90% of the rated currents flowing in its both LV and HV windings, the measured loss is 81 W. The transformer has maximum efficiency when operated at
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- 50.0% of the rated current.
- 64.0% of the rated current.
- 80.0% of the rated current.
- 88.8% of the rated current.
Correct Option: C
P0 = 64 watt
Pcu = 81 watt at 90% of rated load
81 = (0.9 Ifl 2 )R
Ifl 2 R = | = 100 | |
(0.9)2 |
Pcu fl = 100 w
For maximum efficiency

I = 0.81 Ifl