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The single phase, 50Hz, iron core transformer in the circuit has both the vertical arms of cross sectional area 20 cm2 and both the horizontal arms of cross sectional area 10 cm2. If the two windings shown were wound instead on opposite horizontal arms, the mutual inductance will
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- double
- remain same
- be halved
- become one quarter
Correct Option: C
M ∝ √A1 A2
But A1 = A2 = A
∴ M ∝ A
| ∴ M2 = | . M1 = | M1 = | |||
| A1 | 20 | 2 |
Since M = √L1 L2
| where L1 = | and φi = B1 A1 | |
| Li |
| ∴ M ∝ √A1 A2 × L1 = | ||
| Li |
Alternately
L = μ0 nA
∴ M = k √L1 L2
