-
A braced cut, 5 m wide and 7.5 m deep is proposed in a cohesion less soil deposit having effective cohesion c’ = 0 and effective friction angle, φ’ = 36°. The first row of struts is to be installed a depth of 0.5 m below ground surface and spacing between the struts should be 1.5 m. If the horizontal spacing of struts is 3 m and unit weight of the deposit is 20kN/m3, the maximum strut load will be
-
- 70.87 kN
- 98.72 kN
- 113.90 kN
- 151.86 kN
Correct Option: C
Number of struts
= | 1.5 |
= 4.67 ≈ 5
Maximum force will be at centre.
Active earth pressure,
σ1 = σ3 = tan α – 2 c tan α
γz = α3 tan2 α
20 × 7.5 = σ3 tan2 | 45 + | 2 |
= σ3 tan2 | 45 + | 2 |
⇒ 150 = σ3 × 3.85
∴ σ3 = 38.96 kN/m2
Uniform pressure = 0.65 × σ3
= 0.65 × 38.96 = 25.32
∴ Maximum force on a street at middle
= 25.32 × 3 × 1.5 = 113.9 kN