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A bracket connection is made with four bolts of 10 mm diameter and supports a load of 10 kN at an eccentricity of 100 m. The maximum force to be resisted by any bolt will be
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- 5 kN
- 6.5 kN
- 6.8 kN
- 7.16 kN
Correct Option: D
Vertical load resisted/bolt = 10/4 = 2.5 kN
Torsion, T = 10 × 100 = 1000 kNm.
Radial distance of bolt = √302 + 402 = 50 mm
∴ Torsion shear = | Σ r2 |
= 5 kN | (4 × 50)2 |
θ = tan- 1 | ![]() | ![]() | = 36.9° | 40 |
Resultant R = √2.52 + 52 + 2 × 2.5 × 5 × cos36.9°
= 7.16 kN