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What is the corona loss of a 3 – φ line, 160 km long, conductor diameter 1.036 cm, 2.44 delta spacing, air temperature 26°, corresponding to a barometric pressure of 72 cm, operating voltage 110 kV at 50 Hz. m = 0.78?
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- 322 kW
- 792 kW
- 800 kW
- 841 kW
Correct Option: D
Here, L = 160 km; diameter = 1.036;
d = 2.44 m; r = 0.518 cm = 0.518 × 10-2m
| δ = | = | = 0.943 | ||
| 273 + t | 273 + 26 |
∴ Vd = 21.1 × 0.78 × 0.943 × 0.518
| In |  | × 100 |  | = 8.039 × In | | | = 49.47 (Line to neutral) kV. | ||
| 0.518 | 0.518 |
Power Loss
| = 241 × 10-5 | | | × √ | (V - Vd)²kW/phase/km. | ||
| δ | d |
| = 241 × 105 | | | × √ | × 100(63.5 - 9.4)² | ||
| 0.943 | 2.44 |
= (0.1916 × 0.046 × 198.81) = 1.75 kW/phase/km.
= 5.25 kW/km.
= 841 kW for three phases.
